A Pebble Is Dropped From A Building How Far Does The Velocity After 4.0s?Their Times

A pebble is dropped from a building how far does the velocity after 4.0s?their times

 

Good Day

Problem:

a pebble is dropped from a building how far does the velocity after 4.0s?their times

Given Data:

t (time) = 4 seconds

Vi (initial velocity) = 0 m/s

a (acceleration g) = 9.8 m/s²

d (distance)  = ? unknown

Solution:

We can solve the problem using the formula d = 1/2at² since Vi = 0 m/s

d = 1/2at²

  = 1/2× 9.8 m/s² ×(4 s)²

  = 4.9 m/s² × 16 s²

  = 78.4 meters

Answer:

the distance or height is 78.4 meters